Question:

Which one of the following graphs between molar conductivity (\(\Lambda_m\)) versus \(\sqrt{C}\) is correct ?

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Strong electrolytes follow Kohlrausch's law, Lm = L0 - A sqrt(C): straight lines with the same slope for the same type of electrolyte, and KCl has a larger limiting molar conductivity than NaCl.
Updated On: Nov 5, 2026
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The Correct Option is A

Solution and Explanation

For strong electrolytes \(\Lambda_m=\Lambda_m^{0}-A\sqrt{C}\), a straight line with intercept \(\Lambda_m^{0}\) and slope \(-A\).
KCl and NaCl are both 1:1 electrolytes, so the constant \(A\) is the same: the two lines are parallel and cannot cross (this eliminates options 2 and 4).
\(\Lambda_m^{0}(\mathrm{KCl})=\lambda^{0}_{K^+}+\lambda^{0}_{Cl^-}=73.5+76.3\approx149.8\) is greater than \(\Lambda_m^{0}(\mathrm{NaCl})=50.1+76.3\approx126.4\ \mathrm{S\,cm^2\,mol^{-1}}\), so the KCl line lies above the NaCl line (this eliminates option 3).
Option (1) shows two parallel lines with KCl above NaCl.
Answer: (1) graph (1): parallel lines with KCl above NaCl
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