Step 1: Recall the structure of glucose.
In its open-chain form, glucose contains an aldehyde group and five hydroxyl groups.
Step 2: Formation of intramolecular hemiacetal.
When glucose cyclizes, the hydroxyl group on C-5 reacts with the aldehyde group at C-1 to form a hemiacetal.
This results in a six-membered ring (pyranose form).
Step 3: Identify the change in chirality.
The carbonyl carbon (C-1), which was achiral in the open-chain form, now becomes a new chiral center after ring formation.
This leads to two possible stereoisomers, called α- and β-anomers.
Step 4: Conclusion.
Thus, during intramolecular hemiacetal formation, glucose gains an additional chiral carbon.