Which one of the following compounds is the simplest alkane that is optically active?

The question asks for the simplest alkane that is optically active. An alkane is considered optically active if it has at least one chiral center. A chiral center is a carbon atom bonded to four different substituents.
Let's examine each option to identify which one is optically active:

Therefore, the simplest alkane that is optically active is the one in option (A), which contains a chiral center.
Conclusion: The correct answer is option (A). It is the simplest alkane that is optically active due to the presence of a chiral center.
| Group I | Group II |
| P) NaCl | 1) Coordination bond |
| Q) $H_2$ | 2) Polar covalent bond |
| R) $Pd-P$ bond in $Pd(PPh_3)_4 | 3) Covalent bond |
| S) $C-Cl$ bond in $CH_3Cl $ | 4) Ionic bond |

