The problem pertains to the properties of the hydrogen atom's electron in a 1s orbital. Let's evaluate each option:
The statement "The total energy of the electron is maximum when it is at a distance \(\mathrm{a}_{0}\) from the nucleus" is incorrect because the energy of the electron in its orbit depends on its energy level, not its specific location within an orbital. The energy is quantized and constant for a given level.
Therefore, the correct answer is: The total energy of the electron is maximum when it is at a distance \(\mathrm{a}_{0}\) from the nucleus.
1. Probability density: - The probability density of finding the electron is maximum at the nucleus.
2. Distance from the nucleus: - The electron can be found at a distance $2 \mathrm{a}_{0}$ from the nucleus.
3. Spherical symmetry: - The 1s orbital is spherically symmetrical.
4. Total energy: - The total energy of the electron is maximum when it is at a distance $\mathrm{a}_{0}$ from the nucleus.
This statement is incorrect. Therefore, the correct answer is (4).
The figures below show:
Which of the following points in Figure 2 most accurately represents the nodal surface shown in Figure 1?
The wavelength of spectral line obtained in the spectrum of Li$^{2+}$ ion, when the transition takes place between two levels whose sum is 4 and difference is 2, is
A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.