Choose the correct option having all the elements with \( d^{10} \) electronic configuration from the following:
- \( {}^{27}\text{Co}, {}^{28}\text{Ni}, {}^{26}\text{Fe}, {}^{24}\text{Cr} \)
- \( {}^{29}\text{Cu}, {}^{30}\text{Zn}, {}^{48}\text{Cd}, {}^{47}\text{Ag} \)
- \( {}^{46}\text{Pd}, {}^{28}\text{Ni}, {}^{26}\text{Fe}, {}^{24}\text{Cr} \)
- \( {}^{28}\text{Ni}, {}^{24}\text{Cr}, {}^{26}\text{Fe}, {}^{29}\text{Cu} \)
The Correct Option is B
Approach Solution - 1
The question asks which set of elements all possess a \( d^{10} \) electronic configuration. Let's evaluate each element in the given options by determining their electronic configurations and identifying those with a completely filled \( d \)-subshell.
- \({}^{29}\text{Cu}\) (Copper): The electronic configuration of Copper is \([ \text{Ar} ] 3d^{10} 4s^1\). In this case, the \( 3d \) subshell is completely filled with 10 electrons, so it has a \( d^{10} \) configuration.
- \({}^{30}\text{Zn}\) (Zinc): The electronic configuration of Zinc is \([ \text{Ar} ] 3d^{10} 4s^2\). Similar to copper, the \( 3d \) subshell is completely filled with 10 electrons, which gives it a \( d^{10} \) configuration.
- \({}^{48}\text{Cd}\) (Cadmium): The electronic configuration of Cadmium is \([ \text{Kr} ] 4d^{10} 5s^2\). Here, the \( 4d \) subshell is completely filled with 10 electrons, resulting in a \( d^{10} \) configuration.
- \({}^{47}\text{Ag}\) (Silver): The electronic configuration of Silver is \([ \text{Kr} ] 4d^{10} 5s^1\). The \( 4d \) subshell is completely filled with 10 electrons, giving it a \( d^{10} \) configuration.
On evaluating the individual electronic configurations for each of the elements provided in this option, all of them possess a \( d^{10} \) electronic configuration. Therefore, the correct answer consists of elements \({}^{29}\text{Cu}, {}^{30}\text{Zn}, {}^{48}\text{Cd}, {}^{47}\text{Ag}\).
Approach Solution -2
Elements such as Cu, Zn, Ag, and Cd exhibit a \(d^{10}\) electronic configuration:
- \([ \text{Cu} ] = [ \text{Ar} ] 3d^{10} 4s^1\),
- \([ \text{Zn} ] = [ \text{Ar} ] 3d^{10} 4s^2\),
- \([ \text{Ag} ] = [ \text{Kr} ] 4d^{10} 5s^1\),
- \([ \text{Cd} ] = [ \text{Kr} ] 4d^{10} 5s^2\).
The Correct answer is: \( {}^{29}\text{Cu}, {}^{30}\text{Zn}, {}^{48}\text{Cd}, {}^{47}\text{Ag} \)
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