Which one of the figures correctly represents the T–S diagram of a Carnot engine? 
Step 1: Recall the Carnot cycle in the T–S plane.
A Carnot cycle consists of two isothermal processes and two adiabatic processes.
In a T–S diagram:
- Isothermals appear as horizontal lines (constant temperature).
- Adiabatic processes appear as vertical lines (since entropy remains constant).
Step 2: Identify the correct rectangular shape.
A Carnot engine forms a perfect rectangle in the T–S plane:
- Top and bottom edges: isothermal expansion and compression.
- Left and right edges: adiabatic compression and expansion.
Step 3: Compare with the given diagrams.
Only diagram (B) shows a proper rectangle with horizontal and vertical sides, matching the structure of a Carnot cycle.
Step 4: Conclusion.
Thus the correct T–S diagram for a Carnot engine is option (B).

At a particular temperature T, Planck's energy density of black body radiation in terms of frequency is \(\rho_T(\nu) = 8 \times 10^{-18} \text{ J/m}^3 \text{ Hz}^{-1}\) at \(\nu = 3 \times 10^{14}\) Hz. Then Planck's energy density \(\rho_T(\lambda)\) at the corresponding wavelength (\(\lambda\)) has the value \rule{1cm}{0.15mm} \(\times 10^2 \text{ J/m}^4\). (in integer)
[Speed of light \(c = 3 \times 10^8\) m/s]
(Note: The unit for \(\rho_T(\nu)\) in the original problem was given as J/m³, which is dimensionally incorrect for a spectral density. The correct unit J/(m³·Hz) or J·s/m³ is used here for the solution.)

