Which of the following will react with \(\mathrm{CHCl_3}\) + alc. KOH ?
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- Adenine and proline
- Adenine and thymine
- Adenine and lysine
- Thymine and proline
The Correct Option is C
Solution and Explanation
Step 2: Adenine has a free primary amino group (6-aminopurine): reacts.
Step 3: Lysine has two primary amino groups (\(\alpha\) and \(\varepsilon\)): reacts.
Step 4: Thymine has no free \(\mathrm{-NH_2}\) (only amide-type N-H in the ring): does not react. Proline has a secondary amine (cyclic imino group): does not react.
Step 5: So the pair that reacts is adenine and lysine.
Answer: (3) Adenine and lysine
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