To solve the given question, we need to correctly match each biopolymer listed in List I with its corresponding monomer from List II.
Based on these matches, the correct option is: A-II, B-III, C-I, D-IV.
| List I (Bio Polymer) | List II (Monomer) |
|---|---|
| A. Starch | II. \(\alpha\)-glucose |
| B. Cellulose | III. \(\beta\)-glucose |
| C. Nucleic acid | I. nucleotide |
| D. Protein | IV. \(\alpha\)-amino acid |
The correct matching is as follows:
- A. Starch is made up of \( \alpha \)-glucose, so \( A - II \).
- B. Cellulose is made up of \( \beta \)-glucose, so \( B - III \).
- C. Nucleic acid is made up of nucleotides, so \( C - I \).
- D. Protein is made up of amino acids, so \( D - IV \).
Hence, the correct matching is \( A - II, B - III, C - I, D - IV \).
The Correct Answer is: \( A - II, B - III, C - I, D - IV \)
A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.
Inductance of a coil with \(10^4\) turns is \(10\,\text{mH}\) and it is connected to a DC source of \(10\,\text{V}\) with internal resistance \(10\,\Omega\). The energy density in the inductor when the current reaches \( \left(\frac{1}{e}\right) \) of its maximum value is \[ \alpha \pi \times \frac{1}{e^2}\ \text{J m}^{-3}. \] The value of \( \alpha \) is _________.
\[ (\mu_0 = 4\pi \times 10^{-7}\ \text{TmA}^{-1}) \]