(A) False. The complement of a recursively enumerable language is not necessarily recursively enumerable, hence not every subset of a recursively enumerable language is recursive.
(B) True. If both a language and its complement are recursively enumerable, it implies that both the language and its complement are decidable (i.e., recursive), so \(L\) must be recursive.
(C) True. The complement of a context-free language is not necessarily context-free, but it must be recursive, as context-free languages are closed under complementation.
(D) True. If \(L_1\) and \(L_2\) are regular, then their intersection is deterministic context-free. This follows from closure properties of regular and deterministic context-free languages.