To determine which statements about Zn, Cd, and Hg are correct, let's evaluate each option provided:
Considering the evaluation:
Therefore, the correct answer is: B, D only.
- (A) Incorrect. Zn, Cd, and Hg exhibit lower enthalpy of atomization compared to other transition metals in their respective series because they have fully filled d-subshells, which make their bonding weaker.
- (B) Correct. Zn and Cd do not show variable oxidation states, generally remaining in the \( +2 \) state. Hg, however, can show \( +1 \) and \( +2 \) oxidation states due to its unique electron configuration.
- (C) Incorrect. Compounds of Zn, Cd, and Hg are typically diamagnetic because they have fully filled d-orbitals, which do not contribute to unpaired electrons.
- (D) Correct. Zn, Cd, and Hg are known as soft metals due to their malleability and ductility.
The Correct Answer is: B, D only
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)