Given below are two statements:
Statement (I) : Fusion of MnO$_2$ with KOH and an oxidising agent gives dark green K$_2$MnO$_4$.
Statement (II) : Manganate ion on electrolytic oxidation in alkaline medium gives permanganate ion.
In the light of the above statements, choose the correct answer from the options given below.
Statement (I) : Fusion of MnO$_2$ with KOH and an oxidising agent gives dark green K$_2$MnO$_4$.
Statement (II) : Manganate ion on electrolytic oxidation in alkaline medium gives permanganate ion.
In the light of the above statements, choose the correct answer from the options given below.
- Both Statement I and Statement II is true
- Both Statement I and Statement II is false
- Statement I is true but Statement II is false
- Statement I is false but Statement II is true
The Correct Option is A
Approach Solution - 1
The question provides two statements related to the chemistry of manganese compounds, and we need to determine the veracity of these statements based on chemical reactions and principles.
Statement I: Fusion of \(MnO_2\) with \(KOH\) and an oxidising agent gives dark green \(K_2MnO_4\).
Explanation: When manganese dioxide (\(MnO_2\)) is fused with potassium hydroxide (\(KOH\)) in the presence of an oxidizing agent such as chlorine (\(Cl_2\)) or potassium nitrate (\(KNO_3\)), it forms potassium manganate (\(K_2MnO_4\)), which is dark green.
This reaction can be represented as: \(2MnO_2 + 4KOH + O_2 \rightarrow 2K_2MnO_4 + 2H_2O\)
Therefore, Statement I is true.
Statement II: Manganate ion on electrolytic oxidation in alkaline medium gives permanganate ion.
Explanation: In alkaline medium, the manganate ion (\(MnO_4^{2-}\)) can undergo further oxidation to form permanganate ion (\(MnO_4^{-}\)), especially under electrolytic conditions. This transformation occurs due to the gain of an electron by \(MnO_4^{2-}\):
\(MnO_4^{2-} \ + \ e^- + \ H_2O \rightarrow \ MnO_4^- + 2OH^-\)
This shows an increase in oxidation state from Mn (+6 in manganate) to Mn (+7 in permanganate).
Hence, Statement II is also true.
Conclusion: Based on the explanations, both Statement I and Statement II are true. Therefore, the correct answer is: Both Statement I and Statement II is true.
Approach Solution -2
Statement I: True. Fusion of MnO$_2$ with KOH in the presence of oxygen gives K$_2$MnO$_4$ (potassium manganate), which is dark green in color: \[ \text{MnO}_2 + 4\text{KOH} + \text{O}_2 \xrightarrow{\text{fusion}} 2\text{K}_2\text{MnO}_4 + 2\text{H}_2\text{O}. \]
Statement II: True. In alkaline medium, the manganate ion (MnO$_4^{2-}$) undergoes electrolytic oxidation to form the permanganate ion (MnO$_4^-$): \[ \text{MnO}_4^{2-} \rightarrow \text{MnO}_4^- + e^-. \]
Both statements are correct as they describe valid chemical processes.
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