Concept:
In FCC crystals:
• Octahedral sites are located at the center of the unit cell and edge centers
• Tetrahedral sites are located at $(\frac{1}{4},\frac{1}{4},\frac{1}{4})$
Step 1: Identify octahedral site.
The body center position:
\[
\left(\frac{1}{2},\frac{1}{2},\frac{1}{2}\right)
\]
is a classic octahedral interstitial position in FCC.
Step 2: Differentiate from tetrahedral site.
• $(\frac{1}{4},\frac{1}{4},\frac{1}{4})$ → tetrahedral site
• $(\frac{1}{2},\frac{1}{2},\frac{1}{2})$ → octahedral site
Final Answer:
\[
\boxed{\left(\frac{1}{2},\frac{1}{2},\frac{1}{2}\right)}
\]