Which of the following properties will change when system containing solution 1 will become solution 2 ? 
To determine which property will change when the system transitions from Solution 1 to Solution 2, let’s analyze each option based on the changes depicted in the diagram.
Therefore, the correct answer is Gibbs free energy, as the change from Solution 1 to Solution 2 impacts the system’s thermodynamic properties.
Sol. Both solutions are having same composition, which is 1 mole of 'x' in 1L \( H_2O \), so all the intensive properties will remain same, but as total amount is greater in solution '1' compared to solution '2'.
So extensive properties will be different hence Gibbs free energy will be different.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
| Sample | Van't Haff Factor |
|---|---|
| Sample - 1 (0.1 M) | \(i_1\) |
| Sample - 2 (0.01 M) | \(i_2\) |
| Sample - 3 (0.001 M) | \(i_2\) |
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)