The problem requires determining the volume of 3 M NaOH solution that can be prepared from 84 g of NaOH. We begin by finding the number of moles of NaOH from the given mass:
1. Determine the number of moles using the formula:
moles of NaOH = mass of NaOH / molar mass of NaOH.
Given:
Calculate the moles:
2. To find the volume of a 3 M solution, use the formula: Molarity (M) = moles of solute / volume of solution in liters.
Solve for volume:
Convert volume from liters to dm³:
3. The requested format is \( \_ \times 10^{-1} \, \text{dm}^3 \). Expressing 0.7 as 7 × 10-1 dm³ ensures it conforms to this format.
Finally, verify if this value meets the range 7,7. Given that 7 × 10-1 = 0.7, it fits the specified range.
The volume of 3 M NaOH solution that can be prepared is 7 × 10-1 dm³.
The molarity formula is given by: \(M = \frac{n_{\text{NaOH}}}{V_{\text{sol}}},\)
where:
- \( M \) is the molarity (in mol/L),
- \( n_{\text{NaOH}} \) is the number of moles of NaOH,
- \( V_{\text{sol}} \) is the volume of the solution (in liters).
Given:
- \( M = 3 \, \text{M} \),
- Mass of NaOH = \( 84 \, \text{g} \),
- Molar mass of NaOH = \( 40 \, \text{g/mol} \).
Step 1: Calculate the number of moles of NaOH
\(n_{\text{NaOH}} = \frac{\text{Mass of NaOH}}{\text{Molar mass}} = \frac{84}{40} = 2.1 \, \text{moles}.\)
Step 2: Calculate the volume of the solution using the molarity formula
\(V_{\text{sol}} = \frac{n_{\text{NaOH}}}{M} = \frac{2.1}{3} = 0.7 \, \text{L}.\)
Expressing the volume in scientific notation:
\(V_{\text{sol}} = 7 \times 10^{-1} \, \text{L}.\)
Final Answer: \(V_{\text{sol}} = 0.7 \, \text{L or } 7 \times 10^{-1} \, \text{L}.\)
The Correct answer is: 7
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
| Sample | Van't Haff Factor |
|---|---|
| Sample - 1 (0.1 M) | \(i_1\) |
| Sample - 2 (0.01 M) | \(i_2\) |
| Sample - 3 (0.001 M) | \(i_2\) |
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,