Bond energy: \( F_2 > \text{Cl}_2 > \text{Br}_2 \)
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The Correct Option isD
Solution and Explanation
Step 1: Understand bond energy.
The bond energy of \( F_2 \) is lower than that of \( \text{Cl}_2 \) and \( \text{Br}_2 \) due to the small size of the fluorine atoms, which causes electron-electron repulsion.
Step 2: Conclusion.
The incorrect property is bond energy, as \( F_2 \) has a lower bond energy compared to \( \text{Cl}_2 \) and \( \text{Br}_2 \).
Final Answer:
\[
\boxed{\text{Bond energy: } F_2 > \text{Cl}_2 > \text{Br}_2}
\]