Question:

Which of the following is incorrect with respect to property indicated?

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Bond energies generally decrease with increasing size of the halogen atoms, making \( F_2 \) weaker than \( \text{Cl}_2 \) and \( \text{Br}_2 \).
Updated On: Mar 25, 2026
  • \( \text{E.N.} F > \text{Cl} > \text{Br} \)
  • \( \text{E.A.} : \text{O} > \text{F} > \text{Br} \)
  • Oxidizing power: \( F_2 > \text{Cl}_2 > \text{Br}_2 \)
  • Bond energy: \( F_2 > \text{Cl}_2 > \text{Br}_2 \)
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The Correct Option is D

Solution and Explanation


Step 1: Understand bond energy.

The bond energy of \( F_2 \) is lower than that of \( \text{Cl}_2 \) and \( \text{Br}_2 \) due to the small size of the fluorine atoms, which causes electron-electron repulsion.
Step 2: Conclusion.

The incorrect property is bond energy, as \( F_2 \) has a lower bond energy compared to \( \text{Cl}_2 \) and \( \text{Br}_2 \). Final Answer: \[ \boxed{\text{Bond energy: } F_2 > \text{Cl}_2 > \text{Br}_2} \]
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