Concept:
The given circuit is a two-level biased clipper (limiter).
• Diode \(D_1\) limits the positive excursion of the output.
• Diode \(D_2\) limits the negative excursion of the output.
Whenever the input tries to exceed the preset clipping level, the corresponding diode conducts and clamps the output voltage.
Step 1: Examine the operation for moderate input voltages.
When
\[
-V_{R2}<v_i<V_{R1},
\]
both diodes remain reverse biased.
Hence neither diode conducts.
Therefore,
\[
v_o=v_i.
\]
Thus option (A) cannot be correct because it states that \(D_2\) is ON and \(v_o=V_{R1}\).
Step 2: Consider large positive input voltage.
When
\[
v_i>V_{R1},
\]
diode \(D_1\) becomes forward biased.
The output gets clamped at
\[
v_o \approx V_{R1}.
\]
At this time \(D_2\) remains OFF.
Step 3: Consider large negative input voltage.
When
\[
v_i<-V_{R2},
\]
the output attempts to become more negative than the reference level.
Diode \(D_2\) becomes forward biased and conducts.
Hence the output is prevented from decreasing further and is clamped at
\[
v_o=-V_{R2}.
\]
During this condition,
\[
D_1 \text{ is OFF}
\]
and
\[
D_2 \text{ is ON}.
\]
Step 4: Match with the given options.
The correct operating condition is
\[
-V_{R2}>v_i
\]
\[
D_1 \text{ OFF}
\]
\[
D_2 \text{ ON}
\]
\[
v_o=-V_{R2}.
\]
Therefore,
\[
\boxed{
-V_{R2}>v_i
\Rightarrow
D_1 \text{ OFF},
D_2 \text{ ON}
\Rightarrow
v_o=-V_{R2}
}
\]
which corresponds to option (D).