The question asks for the correct order of stability among isobutene, trans-2-butene, cis-2-butene, and but-1-ene. Alkene stability rises with more alkyl substitution on the double bond carbons through hyperconjugation, and among similarly substituted alkenes, the trans form beats the cis form because the cis form has more steric clash between the two alkyl groups sitting on the same side. Using these two rules, each answer option can be checked directly.
Checking every option against the substitution and steric strain rules leaves only one order that is consistent all the way through.
So the correct answer is Isobutene > Trans-2-butene > Cis-2-Butene > but-1-ene.
List I | List II | ||
|---|---|---|---|
| A | \(\Omega^{-1}\) | I | Specific conductance |
| B | \(∧\) | II | Electrical conductance |
| C | k | III | Specific resistance |
| D | \(\rho\) | IV | Equivalent conductance |
List I | List II | ||
|---|---|---|---|
| A | Constant heat (q = 0) | I | Isothermal |
| B | Reversible process at constant temperature (dT = 0) | II | Isometric |
| C | Constant volume (dV = 0) | III | Adiabatic |
| D | Constant pressure (dP = 0) | IV | Isobar |
List I | List II | ||
|---|---|---|---|
| A | \(\Omega^{-1}\) | I | Specific conductance |
| B | \(∧\) | II | Electrical conductance |
| C | k | III | Specific resistance |
| D | \(\rho\) | IV | Equivalent conductance |
List I | List II | ||
|---|---|---|---|
| A | Constant heat (q = 0) | I | Isothermal |
| B | Reversible process at constant temperature (dT = 0) | II | Isometric |
| C | Constant volume (dV = 0) | III | Adiabatic |
| D | Constant pressure (dP = 0) | IV | Isobar |