Which of the following circuits represents a forward biased diode?
To determine which circuits represent a forward biased diode, we need to understand the behavior of a diode in a circuit. A diode is forward biased when the anode (positive side) is connected to a higher potential than the cathode (negative side). This allows current to flow through the diode.
Let's analyze the provided options:
Upon evaluating the potential differences in the circuits shown in the original problem, it is clear that options (B), (C), and (E) have the diodes in a forward biased state.
Therefore, the correct answer is: (B), (C), and (E) only.
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,



The output voltage in the following circuit is (Consider ideal diode case): 
In the following circuit, the reading of the ammeter will be: (Take Zener breakdown voltage = 4 V)
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)