\(H_2O\)
\(NH_3\)
\(HBr\)
\(HCl\)
Ammonia \((NH_3)\) can form linear chains or polymers through hydrogen bonding between ammonia molecules, leading to the formation of \(NH_3NH_3NH_3.….\) chains. This hydrogen bonding is responsible for some of the unique properties of ammonia, such as its high boiling and melting points.
So, the correct option is (B): \(NH_3\)
| Column I | Column II | ||
|---|---|---|---|
| (a) | $XX'$ | (i) | T-shape |
| (b) | $XX'_3$ | (ii) | Pentagonal bipyramidal |
| (c) | $XX'_5$ | (iii) | Linear |
| (d) | $XX'_7$ | (iv) | Square-pyramidal |
| (v) | Tetrahedral | ||
| List-I (Oxoacids of Sulphur) | List-II (Bonds) | ||
| A | Peroxodisulphuric acid | I | Two S–OH, Four S=O, One S–O–S |
| B | Sulphuric acid | II | Two S–OH, One S=O |
| C | Pyrosulphuric acid | III | Two S–OH, Four S=O, One S–O–O–S |
| D | Sulphurous acid | IV | Two S–OH, Two S=O |