Concept:
A Binary Search Tree (BST) satisfies the property:
\[
\text{Left Subtree}
<
\text{Root}
<
\text{Right Subtree}
\]
for every node.
Tree traversal methods include:
• Pre-order
• In-order
• Post-order
• Level-order
Among these, in-order traversal produces the elements in sorted order.
Step 1: Recall In-order traversal.
In-order traversal follows:
\[
\text{Left} \rightarrow \text{Root} \rightarrow \text{Right}
\]
Step 2: Apply BST property.
Since every left child contains smaller values and every right child contains larger values,
visiting:
\[
\text{Left} \rightarrow \text{Root} \rightarrow \text{Right}
\]
automatically generates elements in ascending order.
Step 3: Illustration.
Consider:
\[
\begin{array}{c}
20
/ \ \backslash
10 \ \ 30
\end{array}
\]
In-order traversal gives:
\[
10,20,30
\]
which is sorted.
Step 4: Write the answer.
Therefore,
\[
\boxed{\text{In-order Traversal}}
\]
gives sorted order.
Hence option (D) is correct.