Question:
What is the minimum number of edges possible in a directed graph having 6 vertices and no self-loops?
What is the minimum number of edges possible in a directed graph having 6 vertices and no self-loops?
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For directed graphs without self-loops, use the formula \(n(n-1)\) to find edge count.
Updated On: May 26, 2025
- 5
- 30
- 36
- 216
Show Solution
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The Correct Option is B
Solution and Explanation
In a directed graph with \(n\) vertices and no self-loops, maximum possible number of edges is \(n(n - 1)\).
\[ n = 6 \Rightarrow 6 \times (6 - 1) = 30 \text{ edges} \]
\[ n = 6 \Rightarrow 6 \times (6 - 1) = 30 \text{ edges} \]
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