When you reverse the digits of the number 13, the number increases by 18. How many other two-digit numbers increase by 18 when their digits are reversed?
Show Hint
Digit reversal problems reduce to linear conditions on digit differences.
Let number = $10a + b$, reverse = $10b + a$. Difference: $(10b + a) - (10a + b) = 9(b-a) = 18 \Rightarrow b-a = 2$.
$a$ can range from 1 to 7 (since $b \leq 9$), excluding $a=1$ for given 13 leaves 6 others.
\[
\boxed{6}
\]