When three identical bulbs of 60 watt 200 volt rating are connected in series to a 200-volt supply, the power drawn by them will be
180 watt
10 watt
20 watt
60 watt
The Correct Option is C
Solution and Explanation
\(\frac{1}{P_{eq}}=\frac{1}{P_1}+\frac{1}{P_2}+\frac{1}{P_3}\)+.......
For this question \(\frac{1}{60}+\frac{1}{60}+\frac{1}{60}\) = \(\frac{3}{60}\) = \(\frac{1}{20}\) \(\Rightarrow\) Peq = 20watt
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