Question:
When dielectric is inserted between the plates of a capacitor with battery connected, energy increases because of:
When dielectric is inserted between the plates of a capacitor with battery connected, energy increases because of:
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Battery connected = Voltage constant; Dielectric inserted = Capacitance increases.
Updated On: Jun 6, 2026
- increase in charge
- increase in voltage
- increase in field
- increase in separation between the plates
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The Correct Option is A
Solution and Explanation
Step 1: Concept
Capacitor with battery connected.
Step 2: Meaning
Voltage ($V$) is constant. Capacitance $C$ increases ($C = K C_0$).
Step 3: Analysis
Since $V$ is constant, charge $Q = CV$ increases as $C$ increases. Energy $U = \frac{1}{2} CV^2$ increases because $C$ increases.
Step 4: Conclusion
Energy increases because the capacitance and charge increase.
Final Answer: (A)
Capacitor with battery connected.
Step 2: Meaning
Voltage ($V$) is constant. Capacitance $C$ increases ($C = K C_0$).
Step 3: Analysis
Since $V$ is constant, charge $Q = CV$ increases as $C$ increases. Energy $U = \frac{1}{2} CV^2$ increases because $C$ increases.
Step 4: Conclusion
Energy increases because the capacitance and charge increase.
Final Answer: (A)
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