To solve this question, we need to determine the correct optical aid for a person suffering from both Myopia (nearsightedness) and Hypermetropia (farsightedness).
1. Understanding the Conditions:
- Myopia: Corrected using concave lenses.
- Hypermetropia: Corrected using convex lenses.
2. When Both Conditions Are Present:
A person with both conditions needs correction for both near and distant vision. This is achieved using a bi-focal lens, which has two parts: - The upper part corrects distant vision (myopia). - The lower part corrects near vision (hypermetropia).
3. Analyzing the Options:
- Bi-convex lens: Only for hypermetropia.
- Bi-concave lens: Only for myopia.
- Bi-focal lens: Corrects both.
- Bi-focal mirror: Not used for vision correction.
Final Answer:
Option (C) Bi-focal lens is correct.
\(XPQY\) is a vertical smooth long loop having a total resistance \(R\), where \(PX\) is parallel to \(QY\) and the separation between them is \(l\). A constant magnetic field \(B\) perpendicular to the plane of the loop exists in the entire space. A rod \(CD\) of length \(L\,(L>l)\) and mass \(m\) is made to slide down from rest under gravity as shown. The terminal speed acquired by the rod is _______ m/s. 
A biconvex lens is formed by using two plano-convex lenses as shown in the figure. The refractive index and radius of curvature of surfaces are also mentioned. When an object is placed on the left side of the lens at a distance of \(30\,\text{cm}\), the magnification of the image will be: 