Question:

Boston is 4 hr ahead of Frankfurt and 2 hr behind India. X leaves Frankfurt at 6 p.m. on Friday and reaches Boston the next day. After waiting there for 2 hr, he leaves exactly at noon and reaches India at 1 a.m. On his return journey, he takes the same route as before, but halts at Boston for 1hr less than his previous halt there. He then proceeds to Frankfurt.
What is X's average speed for the entire journey (to and fro)?

Show Hint

Average speed is total distance divided by total time. Check whether the passage gives any distance or speed that applies to this question.
Updated On: Nov 4, 2026
  • Data insufficient
  • 180 mph
  • 165 mph
  • 176 mph
Show Solution
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The Correct Option is A

Solution and Explanation

Step 1: What is needed:
Average speed \( = \dfrac{\text{total distance}}{\text{total time}} \). The total time can be found from the times and time zones: the outward trip takes 25 hr and the return trip takes 24 hr.

Step 2: What is missing:
The passage gives no distance between Frankfurt and India, and no speed for any leg. The speed of 180 mph in the previous question applies only to that question ("If his journey ... is covered at an average speed of 180 mph"). Without a distance or speed for this question, the average speed cannot be found.

Step 3: Cross-check the numbers in the options:
If we did use 180 mph for the outward trip (4,500 miles in 25 hr), the average for the full trip would be \( \dfrac{9000}{49} \approx 183.7 \) mph, which matches none of the numeric options. So the numeric options are not obtainable from the data, and the answer is "Data insufficient".

Final Answer:
The correct option is (1): Data insufficient
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