Concept:
To make a number an integer, we need to examine its fractional part. If the fractional part is \(f\), then the least positive number required to make it an integer is \(1-f\).
Step 1: Separate the integer and fractional parts.
Given,
\[
2\frac{2}{3}+4\frac{7}{12}+6\frac{5}{6}+8\frac{11}{36}
\]
Adding the integer parts,
\[
2+4+6+8=20
\]
Now add the fractional parts:
\[
\frac{2}{3}+\frac{7}{12}+\frac{5}{6}+\frac{11}{36}
\]
Taking LCM of \(3,12,6,36\), we get
\[
36
\]
Hence,
\[
\frac{2}{3}=\frac{24}{36}, \qquad
\frac{7}{12}=\frac{21}{36}, \qquad
\frac{5}{6}=\frac{30}{36}, \qquad
\frac{11}{36}=\frac{11}{36}
\]
Therefore,
\[
\frac{24+21+30+11}{36}
=
\frac{86}{36}
=
\frac{43}{18}
=
2+\frac{7}{18}
\]
Step 2: Find the fractional part of the total sum.
Thus the complete sum is
\[
20+2+\frac{7}{18}
=
22+\frac{7}{18}
\]
The fractional part is
\[
\frac{7}{18}
\]
Step 3: Determine the least number required.
To reach the next integer,
\[
1-\frac{7}{18}
=
\frac{18-7}{18}
=
\frac{11}{18}
\]
Hence the smallest rational number that must be added is
\[
\boxed{\frac{11}{18}}
\]