What is the overall order of the reaction? Rate = k[A]½ [B]3/2
- 2
- 0
- 1
- 0.5
The Correct Option is A
Approach Solution - 1
The overall order of a chemical reaction is determined by summing the exponents of the concentration terms in the rate law expression. Given the rate law for the reaction:
Rate = k[A]½ [B]3/2
Here, [A]½ indicates the reaction is first-order with respect to A but raised to the power of ½, and [B]3/2 indicates a reaction order of 3/2 with respect to B.
To find the overall reaction order, sum the exponents:
1. Exponent of [A] = ½
2. Exponent of [B] = 3/2
3. Overall order = ½ + 3/2 = 2
Thus, the overall order of the reaction is 2.
Approach Solution -2
The given rate law for the reaction is:
Rate = k[A]½ [B]3/2
To determine the overall order of the reaction, we need to add the exponents of the concentration terms in the rate law. The order with respect to each reactant is given by the power of its concentration in the rate equation.
- The order with respect to [A] is ½.
- The order with respect to [B] is 3/2.
The overall order of the reaction is the sum of these individual orders:
Overall Order = ½ + 3/2
Performing the addition:
Overall Order = 0.5 + 1.5 = 2
Therefore, the overall order of the reaction is 2.
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