Question

What is the output of the following program?
#include int main() 
{ int fun(int); int i = fun(10); printf("%d\n", --i); 
return 0; } int fun(int i) 
{ return (i++); } 

• A. 9
• B. 10
• C. 11
• D. 8

Hint:

Post-increment returns original value before increasing it. Use pre/post carefully in return statements.

Answer 1

The Correct Option is A

In fun(10), the value returned is 10 because \(i++\) returns the current value before incrementing. So \(i = 10\), and then --i = 9 is printed.