Concept:
The hydrogen spectrum consists of several spectral series that arise due to the transition of an electron from a higher energy level to a lower energy level.
The wavelength of the emitted radiation is given by the
Rydberg Formula,
\[
\frac{1}{\lambda}
=
R\left(\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}}\right),
\]
where
\[
R=1.097\times10^{7}\;m^{-1}
\]
is the Rydberg constant,
\[
n_{1}=\text{lower energy level},
\]
\[
n_{2}=\text{higher energy level}, \qquad n_{2}\gt n_{1}.
\]
For the
Lyman series,
\[
n_{1}=1,
\]
and the electron falls from higher energy levels to the ground state.
The
minimum wavelength (also called the series limit) is obtained when
\[
n_{2}\rightarrow\infty.
\]
Step 1: Write the Rydberg formula for the Lyman series.
For the Lyman series,
\[
n_{1}=1.
\]
Hence,
\[
\frac{1}{\lambda}
=
R
\left(
1-\frac{1}{n_{2}^{2}}
\right).
\]
Step 2: Find the limiting wavelength.
The minimum wavelength corresponds to the highest possible transition,
\[
n_{2}\rightarrow\infty.
\]
Therefore,
\[
\frac{1}{n_{2}^{2}}
=
0.
\]
Substituting,
\[
\frac{1}{\lambda_{\min}}
=
R.
\]
Thus,
\[
\lambda_{\min}
=
\frac{1}{R}.
\]
Step 3: Substitute the value of the Rydberg constant.
Using,
\[
R
=
1.097\times10^{7}\;m^{-1},
\]
we get,
\[
\lambda_{\min}
=
\frac{1}{1.097\times10^{7}}.
\]
Therefore,
\[
\lambda_{\min}
=
9.12\times10^{-8}\;m.
\]
Converting into nanometres,
\[
1\,nm=10^{-9}\,m,
\]
hence,
\[
\lambda_{\min}
=
91.2\,nm.
\]
Thus,
\[
\boxed{\lambda_{\min}=91.2\,nm.}
\]
Therefore, the correct answer is
\[
\boxed{\textbf{Option (A)}}.
\]
Additional Information:
The important hydrogen spectral series are listed below:
\[
\begin{array}{|c|c|c|}
\hline
\textbf{Series} & \mathbf{n_{1}} & \textbf{Region} \\
\hline
\text{Lyman} & 1 & \text{Ultraviolet} \\
\hline
\text{Balmer} & 2 & \text{Visible} \\
\hline
\text{Paschen} & 3 & \text{Infrared} \\
\hline
\text{Brackett} & 4 & \text{Infrared} \\
\hline
\text{Pfund} & 5 & \text{Infrared} \\
\hline
\end{array}
\]
The first line of the Lyman series has wavelength
\[
121.6\,nm,
\]
while the limiting (minimum) wavelength is
\[
91.2\,nm.
\]