Question:
What is the highest possible oxidation state exhibited by manganese ?
What is the highest possible oxidation state exhibited by manganese ?
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Manganese uses all 7 valence electrons (3d5 4s2) to show +7.
Updated On: Oct 1, 2026
- \(+8\)
- \(+5\)
- \(+6\)
- \(+7\)
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The Correct Option is D
Solution and Explanation
Step 1: Understanding the Concept:
The highest oxidation state of a 3d element is usually the sum of its \(4s\) and \(3d\) electrons.
Step 2: Manganese:
Mn has the configuration \([\text{Ar}]3d^5 4s^2\), which has 7 valence electrons. Removing all of them gives \(+7\), as in \(\text{KMnO}_4\) and \(\text{Mn}_2\text{O}_7\).
Step 3: Check the Other Options:
\(+8\) is not possible because there are only 7 electrons available. \(+5\) and \(+6\) are real states (manganate(V) and manganate(VI) ions), but they are not the highest. So (D) is correct.
Final Answer:
The highest oxidation state of Mn is +7, option (D). \[ \boxed{\text{(D) } +7} \]
The highest oxidation state of a 3d element is usually the sum of its \(4s\) and \(3d\) electrons.
Step 2: Manganese:
Mn has the configuration \([\text{Ar}]3d^5 4s^2\), which has 7 valence electrons. Removing all of them gives \(+7\), as in \(\text{KMnO}_4\) and \(\text{Mn}_2\text{O}_7\).
Step 3: Check the Other Options:
\(+8\) is not possible because there are only 7 electrons available. \(+5\) and \(+6\) are real states (manganate(V) and manganate(VI) ions), but they are not the highest. So (D) is correct.
Final Answer:
The highest oxidation state of Mn is +7, option (D). \[ \boxed{\text{(D) } +7} \]
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