Question:

What is the energy of the ground state of a hydrogen atom according to the Bohr model?

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Energy levels of hydrogen follow \[ E_n = -\frac{13.6}{n^2}\ \text{eV} \] The ground state (\(n=1\)) has energy \(-13.6\ \text{eV}\).
Updated On: Mar 25, 2026
  • \(-13.6\ \text{eV}\)
  • \(-3.4\ \text{eV}\)
  • \(-1.51\ \text{eV}\)
  • \(0\ \text{eV}\)
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The Correct Option is A

Solution and Explanation

Concept: According to the Bohr model, the electron in a hydrogen atom can occupy only certain discrete energy levels. The energy of the \(n^{th}\) orbit is given by \[ E_n = -\frac{13.6}{n^2}\ \text{eV} \] where \(n = 1,2,3,\dots\) is the principal quantum number.
Step 1: Identify the ground state.} The ground state corresponds to the lowest possible energy level, which occurs when \[ n = 1 \]
Step 2: Substitute into the energy formula.} \[ E_1 = -\frac{13.6}{1^2} \] \[ E_1 = -13.6\ \text{eV} \] Thus, the energy of the ground state of hydrogen is \(-13.6\ \text{eV}\).
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