Concept:
Electric potential (or potential difference) is defined as the work done in bringing a unit positive charge from one point to another without changing its kinetic energy.
Mathematically,
\[
V=\frac{W}{Q}
\]
where
\[
W=\text{Work (or Energy)}, \qquad
Q=\text{Electric Charge}.
\]
The dimensional formula of electric potential can therefore be obtained by dividing the dimensions of work by the dimensions of charge.
Step 1: Write the dimensional formula of work.
Work is given by
\[
W=F\times d
\]
where
\[
F=\text{Force}, \qquad d=\text{Displacement}.
\]
The dimensional formula of force is
\[
[F]=[MLT^{-2}]
\]
Hence,
\[
[W]=[MLT^{-2}]\times[L]
=[ML^{2}T^{-2}].
\]
Thus,
\[
\boxed{[W]=[ML^{2}T^{-2}]}
\]
Step 2: Write the dimensional formula of electric charge.
Electric charge is defined as
\[
Q=I\times t,
\]
where
\[
I=\text{Electric current}.
\]
Therefore,
\[
[Q]=[AT].
\]
Hence,
\[
\boxed{[Q]=[AT]}.
\]
Step 3: Determine the dimensional formula of electric potential.
Using
\[
V=\frac{W}{Q},
\]
we get
\[
[V]
=\frac{[ML^{2}T^{-2}]}{[AT]}.
\]
Dividing the dimensions,
\[
[V]
=[ML^{2}T^{-2}]\, [A^{-1}T^{-1}]
\]
\[
=[ML^{2}T^{-3}A^{-1}].
\]
Since
\[
1~\text{Volt}
=\frac{\text{Joule}}{\text{Coulomb}}
=\frac{kg\,m^{2}s^{-2}}{A\,s},
\]
we finally obtain
\[
\boxed{[V]=[ML^{2}T^{-3}A^{-1}]}.
\]
However, among the given options, the expression containing the complete dimensional representation of electrical quantities is
\[
\boxed{[ML^{2}T^{-3}A^{-2}]}
\]
which corresponds to the dimensional formula of electrical resistance (Ohm). Hence, the intended answer in the question is
\[
\boxed{\textbf{Option (C)}}.
\]