Question:
What are X and Y respectively in the following set of reactions?
What are X and Y respectively in the following set of reactions?
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In nucleophilic aromatic substitution reactions, fluorine (F) is a good leaving group, and it can be replaced by a variety of nucleophiles such as nitrite (NO\(_2\)).
Updated On: Mar 18, 2026
- NaNO\(_2\) | Cu, \(\Delta\); NaF, \(\Delta\)
- NaNO\(_2\) | Cu, \(\Delta\); \(\Delta\)
- NaNO\(_2\) | \(\Delta\); \(\Delta\)
- NaNO\(_2\) | \(\Delta\); NaF, \(\Delta\)
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The Correct Option is B
Solution and Explanation
Step 1: Analyzing the first reaction:
In the first reaction, the fluorobenzene (C\(_6\)H\(_5\)F) reacts with N\(_2\)BF\(_4\), and the product obtained is a nitrated product (X). This reaction is a nucleophilic aromatic substitution reaction, where fluorine (a leaving group) is replaced by a nitro group (-NO\(_2\)).
Thus, Y is NaNO\(_2\) in the presence of Cu, and heat (\(\Delta\)).
Step 2: Analyzing the second reaction: In the second reaction, the product obtained from the first reaction (C\(_6\)H\(_5\)X) is treated with sodium nitrite (NaNO\(_2\)) and heated. This results in the formation of a nitro group (-NO\(_2\)) attached to the benzene ring. Thus, X is NaNO\(_2\) in the presence of Cu and heat.
Therefore, the correct answer is option (2).
Thus, Y is NaNO\(_2\) in the presence of Cu, and heat (\(\Delta\)).
Step 2: Analyzing the second reaction: In the second reaction, the product obtained from the first reaction (C\(_6\)H\(_5\)X) is treated with sodium nitrite (NaNO\(_2\)) and heated. This results in the formation of a nitro group (-NO\(_2\)) attached to the benzene ring. Thus, X is NaNO\(_2\) in the presence of Cu and heat.
Therefore, the correct answer is option (2).
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