Identify the sets containing isostructural molecules from the following options:
i: \({SiF}_4\), \({CCl}_4\)
ii: \({NF}_3\), \({XeO}_3\)
iii: \({BeCl}_2\), \({HgCl}_2\)
iv: \({SF}_4\), \({XeF}_4\)
Step 1: Analyze the molecular geometries.
Set i: Both molecules are tetrahedral, sharing identical electron pair geometries.
Set ii: Both molecules have a pyramidal structure, albeit \(<NF_3>\) with bonding pairs and \(<XeO_3>\) with lone pairs affecting the structure.
Set iii: Both are linear, having the simplest geometric arrangement.
Step 2: Comparison with Set iv. Set iv does not contain isostructural molecules due to the different spatial arrangements (\(<SF_4>\) see-saw vs. \(<XeF_4>\) square planar).
One mole of compound AB reacts with one mole of compound CD according to the equation: \[ {AB} + {CD} \rightleftharpoons {AD} + {CB} \] At equilibrium, it was found that \(\frac{3}{4}\) mole of AB and CD had been converted to AD and CB. There is no change in volume. The equilibrium constant for the reaction is: