Question

What are X and Y in the following reaction sequence?
$C_6H_5N_2Cl \xrightarrow[H_2O]{283K} X \xrightarrow[OH^-]{C_6H_5N_2Cl} Y$

• A. 1
• B. 2
• C. 3
• D. 4

Hint:

{Coupling Conditions:} Phenol: Alkaline medium ($pH 9-10$). Aniline: Acidic medium ($pH 4-5$).

Answer 1

The Correct Option is C

Step 1: Hydrolysis of Diazonium Salt:
Benzenediazonium chloride ($C_6H_5N_2Cl$) on warming with water ($> 283\,K$) undergoes hydrolysis to give Phenol ($C_6H_5OH$).
Hence, $X = \text{Phenol}$. 

Step 2: Coupling Reaction:
Phenol ($X$) reacts with benzenediazonium chloride ($C_6H_5N_2Cl$) in alkaline medium ($OH^-$).
This is a Diazo Coupling Reaction.
The $-OH$ group is activating and directs substitution mainly to the para-position (less steric hindrance).
Thus, the product $Y$ is p-hydroxyazobenzene.
Structure: $C_6H_5 - N = N - C_6H_4OH\,(p)$. 

Step 3: Final Answer:
The correct option is (3).