We are given a set of 7 data points (weights of students) and asked to find the median of this data.
The median is the middle value in a dataset that has been arranged in ascending or descending order.
1. Arrange the data in order.
2. If the number of observations (n) is odd, the median is the ((n+1)/(2))-th term.
3. If n is even, the median is the average of the ((n)/(2))-th and ((n)/(2)+1)-th terms.
The given weights are: 44, 42, 40, 47, 41, 38, 45.
First, we arrange these numbers in ascending order:
38, 40, 41, 42, 44, 45, 47
The number of students (observations) is n = 7, which is an odd number.
The position of the median is given by ((n+1)/(2))-th term.
Position = ((7+1)/(2)) = (8)/(2) = 4-th term.
Now we find the 4th term in the ordered list:
1st term = 38
2nd term = 40
3rd term = 41
4th term = 42
5th term = 44
6th term = 45
7th term = 47
The 4th term is
42. Therefore, the median weight is 42.