Question:
Waves having a velocity 10m/s, strike a stationary boat near the sea shore. The distance between two consecutive crests of the waves is 40m. After how many second, the consecutive waves strike the boat?
Waves having a velocity 10m/s, strike a stationary boat near the sea shore. The distance between two consecutive crests of the waves is 40m. After how many second, the consecutive waves strike the boat?
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The time between consecutive crests is the period, which equals wavelength divided by wave speed.
Updated On: Oct 1, 2026
- \(8\) s
- \(6\) s
- \(4\) s
- \(2\) s
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept:
Consecutive crests reach a fixed point after a time equal to the period \(T\) of the wave.
Step 2: Key Formula or Approach:
\[ v = \frac{\lambda}{T} \Rightarrow T = \frac{\lambda}{v} \]
Step 3: Calculate.
\[ T = \frac{40}{10} = 4\text{ s} \]
Step 4: Check the options.
8 s would need a wavelength of 80 m and 2 s would need 20 m.
Final Answer:
Consecutive waves strike the boat every 4 s, option (C). \[ \boxed{4\text{ s}} \]
Consecutive crests reach a fixed point after a time equal to the period \(T\) of the wave.
Step 2: Key Formula or Approach:
\[ v = \frac{\lambda}{T} \Rightarrow T = \frac{\lambda}{v} \]
Step 3: Calculate.
\[ T = \frac{40}{10} = 4\text{ s} \]
Step 4: Check the options.
8 s would need a wavelength of 80 m and 2 s would need 20 m.
Final Answer:
Consecutive waves strike the boat every 4 s, option (C). \[ \boxed{4\text{ s}} \]
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