Question:
Two sea trawlers left a sea port simultaneously in two mutually perpendicular directions. Half an hour later, the shortest distance between them was 17 km and another 15 minutes later, one sea trawler was 10.5 km farther from the original than the other. Find the speed of each sea trawler.
Two sea trawlers left a sea port simultaneously in two mutually perpendicular directions. Half an hour later, the shortest distance between them was 17 km and another 15 minutes later, one sea trawler was 10.5 km farther from the original than the other. Find the speed of each sea trawler.
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The distance between the trawlers at time t is t*sqrt(x^2+y^2); combine this with the difference in distance covered to get two equations in x and y.
Updated On: Jul 14, 2026
- 16 km/hr, 30 km/hr
- 18 km/hr, 24 km/hr
- 20 km/hr, 22 km/hr
- 18 km/hr, 36 km/hr
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The Correct Option is A
Solution and Explanation
d(t)=t*sqrt(x^2+y^2). At t=0.5: sqrt(x^2+y^2)=34 => x^2+y^2=1156. At t=0.75: 0.75(x-y)=10.5 => x-y=14. Squaring: x^2-2xy+y^2=196 => 1156-2xy=196 => xy=480. (x+y)^2=1156+960=2116 => x+y=46. Solving: x=30,y=16.
Final Answer: 16 km/hr and 30 km/hr, option (1).
Final Answer: 16 km/hr and 30 km/hr, option (1).
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