Step 1: Analyze conservation laws.
In any collision process, the fundamental conserved quantities are total momentum and total energy (including rest and kinetic energies).
Step 2: Relativistic collision condition.
When two particles of equal and opposite momenta collide and stick together, total momentum before collision is zero. Hence, after collision, total momentum remains zero β momentum conserved.
Step 3: Check kinetic and rest mass conservation.
Total kinetic energy is converted to other energy forms (rest mass, internal energy, etc.), so it is not conserved. However, total energy (including rest energy) is conserved. Rest mass, on the other hand, changes due to binding energy.
Step 4: Conclusion.
Hence, total momentum and total energy are conserved.
Consider an inertial frame \( S' \) moving at speed \( c/2 \) away from another inertial frame \( S \) along the common x-axis, where \( c \) is the speed of light. As observed from \( S' \), a particle is moving with speed \( c/2 \) in the \( y' \) direction, as shown in the figure. The speed of the particle as seen from \( S \) is: 
Rod $R_1$ has rest length 1 m and rod $R_2$ has rest length 2 m. $R_1$ and $R_2$ move with velocities $+v\hat{i}$ and $-v\hat{i}$ respectively relative to the lab. If $R_2$ has a length of 1 m in the rest frame of $R_1$, $\frac{v}{c}$ is ................... (Specify answer up to two digits after decimal.)