Two radioactive elements A and B initially have the same number of atoms. The half-life of A is the same as the average life of B. If \( \lambda_A \) and \( \lambda_B \) are the decay constants of A and B respectively, then choose the correct relation from the given options:
\( \lambda_A = 2\lambda_B \)
\( \lambda_A = \lambda_B \)
\( \lambda_A \ln 2 = \lambda_B \)
\( \lambda_A = \lambda_B \ln 2 \)
We are given that the half-life of A is the same as the average life of B. The average life \( \tau \) and half-life \( T \) are related to the decay constant \( \lambda \) by the equations: \[ T = \frac{\ln 2}{\lambda} \quad \text{and} \quad \tau = \frac{1}{\lambda} \] Since the half-life of A is the same as the average life of B, we have: \[ \lambda_A = \lambda_B \ln 2 \] Hence, the correct relation is \( \lambda_A = \lambda_B \ln 2 \).
The heat generated in 1 minute between points A and B in the given circuit, when a battery of 9 V with internal resistance of 1 \(\Omega\) is connected across these points is ______ J. 
The given circuit works as: 
Let the lines $L_1 : \vec r = \hat i + 2\hat j + 3\hat k + \lambda(2\hat i + 3\hat j + 4\hat k)$, $\lambda \in \mathbb{R}$ and $L_2 : \vec r = (4\hat i + \hat j) + \mu(5\hat i + + 2\hat j + \hat k)$, $\mu \in \mathbb{R}$ intersect at the point $R$. Let $P$ and $Q$ be the points lying on lines $L_1$ and $L_2$, respectively, such that $|PR|=\sqrt{29}$ and $|PQ|=\sqrt{\frac{47}{3}}$. If the point $P$ lies in the first octant, then $27(QR)^2$ is equal to}