\(\frac{2}{9}F\)
\(\frac{16}{9}F\)
\(\frac{8}{9}F\)
\(F\)

Let the masses are m and distance between them is l, then
F=\(\frac{Gm^2}{I^2}\)
When \(\frac{1}{3^{rd}}\) mass is transferred to the other then masses will be \(\frac{4m}{3}\) and \(\frac{2m}{3}\).
So new force will be
F′=\(G\frac{4m}{3}\)\(\frac{G\frac{4m}{3}×\frac{2m}{3}}{I^2}\)
=\(\frac{8}{9}\)\(\frac{Gm^2}{I^2}\)
=\(\frac{8}{9}F\)
\(\therefore ,\) The correct option is (C): \(\frac{8}{9}F\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,

A body of mass of \(4\;kg\) experiences two forces \(\vec{F_1}=5\hat i+8\hat j+7\hat k \) and \(\vec{F_2}=3\hat i-4\hat j-3\hat k\) then acceleration acting on the body \(R\)
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
Different types of forces that are found in nature can be broadly categorized into two types:
Contact Forces can further be divided into the following types:
Action-at-a-Distance Force is exerted without the objects being in contact. The various types of Action-at-a-Distance Force are as follows: