Two objects \(A\) and \(B\)are placed at \(15\, cm\) and \(25\, cm\) from the pole in front of a concave mirros having radius of curvature \(40\, cm\). The distance between images formed by the mirror is:
Remember the sign conventions for concave mirrors. The mirror formula is essential for solving problems involving image formation.
\(40 \,cm\)
\(160 \,cm\)
\(60 \,cm\)
\(100\, cm\)
The focal length (\(f\)) of a concave mirror is half of its radius of curvature (\(R\)):
\[ f = \frac{R}{2} = \frac{40}{2} = -20 \, \text{cm} \]
The focal length is negative for a concave mirror.
The mirror formula relates the object distance (\(u\)), image distance (\(v\)), and focal length (\(f\)):
\[ \frac{1}{v} + \frac{1}{u} = \frac{1}{f} \]
For object A, \(u_1 = -15 \, \text{cm}\) (negative because the object is in front of the mirror).
\[ \frac{1}{v_1} + \frac{1}{-15} = \frac{1}{-20} \] \[ \frac{1}{v_1} = \frac{1}{15} - \frac{1}{20} = \frac{20 - 15}{300} = \frac{5}{300} = \frac{1}{60} \] \[ v_1 = 60 \, \text{cm} \]
For object B, \(u_2 = -25 \, \text{cm}\):
\[ \frac{1}{v_2} + \frac{1}{-25} = \frac{1}{-20} \] \[ \frac{1}{v_2} = \frac{1}{25} - \frac{1}{20} = \frac{20 - 25}{500} = \frac{-5}{500} = \frac{-1}{100} \] \[ v_2 = -100 \, \text{cm} \]
The image of A is formed at \(v_1 = 60 \, \text{cm}\) (positive, so it’s a real image formed in front of the mirror). The image of B is formed at \(v_2 = -100 \, \text{cm}\) (negative, so it’s a virtual image formed behind the mirror). The distance (\(d\)) between the images is:
\[ d = |v_1| + |v_2| = 60 + 100 = 160 \, \text{cm} \]
The distance between the images is 160 cm (Option 2).
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,



What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
Lenses that are made by combining two spherical transparent surfaces are called spherical lenses. In general, there are two kinds of spherical lenses. Lenses that are made by joining two spherical surfaces that bulge outward are convex lenses, whereas lenses that are made by joining two spherical surfaces that curve inward are concave lenses.