Concept:
Since both trains reach station Q at the same instant, the distances covered by both are equal.
Step 1: Let the common arrival time be \(t\) hours after 2:00 pm.
Then train A travels for
\[
t
\]
hours.
Train B starts 1.5 hours later.
Hence B travels for
\[
t-1.5
\]
hours.
Step 2: Equate distances.
Distance covered by A:
\[
70t
\]
Distance covered by B:
\[
85(t-1.5)
\]
Since both travel between the same stations,
\[
70t=85(t-1.5)
\]
\[
70t=85t-127.5
\]
\[
15t=127.5
\]
\[
t=8.5
\]
Step 3: Determine arrival time.
8.5 hours after 2:00 pm:
\[
2:00\text{ pm}+8\text{ h }30\text{ min}
\]
\[
=10:30\text{ pm}
\]
Therefore,
\[
\boxed{10:30\text{ pm}}
\]