Step 1: Set up variables.
Let the conical tank hold \( x \) litres when full. Then the cylindrical tank holds \( x + 500 \) litres.
Step 2: Use the condition after pumping.
After removing 200 litres from each: cylinder has \( x + 300 \), cone has \( x - 200 \).
Cylinder = 2 times cone: \( x + 300 = 2(x - 200) \).
Step 3: Solve.
\( x + 300 = 2x - 400 \Rightarrow x = 700 \).
Cylindrical tank \( = 700 + 500 = 1200 \) litres.
Step 4: Check.
After pumping: cylinder \( 1000 \), cone \( 500 \); \( 1000 = 2 \times 500 \). Correct. (Option (4), 1000, is what is left in the cylinder, not its full capacity.)
Final Answer:
The correct option is (2): 1200