The sample space for tossing 3 unbiased coins is:
\[
\{TTT, TTH, THT, HTT, HHT, HTH, THH, HHH\}
\]
Given that at least two outcomes are tails, the possible outcomes are:
\[
\{TTT, TTH, THT, HTT\}
\]
Thus, the probability of getting all tails ($TTT$) given that at least two tails appear is:
\[
P(\text{All tails} \mid \text{At least two tails}) = \dfrac{1}{4}
\]
Thus, the correct answer is (B) $\dfrac{1}{4}$.