Pipes A, B and C together fill the tank at a rate of \(1/9\) of the tank per hour. Working together for 3 hours fills \(3 \times 1/9 = 1/3\) of the tank, leaving \(2/3\) still to be filled.
That remaining \(2/3\) gets filled by A and B alone in 12 hours, so their combined rate is \(\dfrac{2/3}{12} = \dfrac{1}{18}\) per hour.
C's individual rate is then \(1/9 - 1/18 = 1/18\), which means C alone would take 18 hours to fill the tank, matching option 2.