Question:
Three consecutive positive even numbers are such that thrice the first number exceeds double the third by 2. Then the third number is
Three consecutive positive even numbers are such that thrice the first number exceeds double the third by 2. Then the third number is
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Let the numbers be x, x + 2, x + 4 and translate the condition into one linear equation.
Updated On: Nov 5, 2026
- 10
- 16
- 14
- 12
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The Correct Option is C
Solution and Explanation
Step 1: Set up:
Let the three consecutive even numbers be \(x,\ x+2,\ x+4\).
Step 2: Condition:
Thrice the first exceeds double the third by 2: \(3x = 2(x+4) + 2\).
Step 3: Solve:
\(3x = 2x + 10 \Rightarrow x = 10\). The numbers are 10, 12, 14.
Step 4: Check:
\(3 \times 10 = 30\) and \(2 \times 14 = 28\); \(30 - 28 = 2\). Correct.
Final Answer:
The third number is 14, so the correct option is (3): 14.
Let the three consecutive even numbers be \(x,\ x+2,\ x+4\).
Step 2: Condition:
Thrice the first exceeds double the third by 2: \(3x = 2(x+4) + 2\).
Step 3: Solve:
\(3x = 2x + 10 \Rightarrow x = 10\). The numbers are 10, 12, 14.
Step 4: Check:
\(3 \times 10 = 30\) and \(2 \times 14 = 28\); \(30 - 28 = 2\). Correct.
Final Answer:
The third number is 14, so the correct option is (3): 14.
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