Question:

There are two sets \(A\) and \(B\) with \(|A|=m\) and \(|B|=n\). If \(|P(A)|-|P(B)|=112\), choose the wrong option.

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Whenever a power set question appears, immediately replace \[ |P(A)|=2^{|A|}. \] Then convert the problem into an equation involving powers of 2.
Updated On: Jun 8, 2026
  • \(m+n=11\)
  • \(2m-n=3\)
  • \(2m-n=1\)
  • \(3n-m=5\)
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The Correct Option is D

Solution and Explanation

Concept: If a set contains \(k\) elements, then its power set contains \[ 2^k \] elements. Therefore, \[ |P(A)|=2^m \] and \[ |P(B)|=2^n. \]

Step 1: Use the given condition.
\[ 2^m-2^n=112 \] Factorizing, \[ 2^n(2^{m-n}-1)=112 \] Now \[ 112=2^4\times7 \] Thus \[ 2^n=16 \] and \[ 2^{m-n}-1=7 \] \[ 2^{m-n}=8 \] \[ m-n=3 \] Hence \[ n=4,\qquad m=7 \]

Step 2: Check each option.
Option (A): \[ m+n=7+4=11 \] True. Option (B): \[ 2m-n=14-4=10 \] Not equal to 1. False. Option (D): \[ 3n-m = 12-7 = 5 \] True. Therefore the wrong option is \[ \boxed{(B)} \]
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