Question:
There are ten boys B1, B2, …, B10 and five girls G1, G2,…, G5 in a class. Then the number of ways of forming a group consisting of three boys and three girls, if both B1 and B2 together should not be the members of a group, is ________
There are ten boys B1, B2, …, B10 and five girls G1, G2,…, G5 in a class. Then the number of ways of forming a group consisting of three boys and three girls, if both B1 and B2 together should not be the members of a group, is ________
Updated On: Mar 17, 2026
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Correct Answer: 1120
Solution and Explanation
The correct answer is 1120
Required number of ways = Total ways of selection – ways in which B1 and B2 are present together.
\(=^{10}C_3⋅^5C_3−^8C_1⋅^5C_3\)
=10(120−8)
= 1120
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